Math, asked by riyabhatkar2007, 5 hours ago


7 \sqrt{48 -  \sqrt{27 -  \sqrt{3} } }
please right answer ​

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Answered by za7318814
0

Answer:

7 \sqrt{48}  -  \sqrt{27}  -  \sqrt{3} \\  = 7 \sqrt{2 \times 2 \times 2 \times 2 \times 3}   -  \sqrt{3 \times 3 \times 3}  -  \sqrt{3}  \\  = 7 \times 4 \sqrt{3}  - 3 \sqrt{3}  -  \sqrt{3}  \\  = 28 \sqrt{3}  - 3 \sqrt{3}  -  \sqrt{3 }  \\   = 28 \sqrt{3}  - 4 \sqrt{3}  \\  = 24 \sqrt{3}

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