Question

$7^{x+y} = 343 and 343x^{x-y} = 7$
pls tell solution

Answer 1

Answer:

Step-by-step explanation:

Given that

$7^{x+y} = 343\\=> 7^{x+y} = 7 * 49\\=> 7^{x+y} = 7^3\\=> x + y = 3$

and

$343x^{x-y} = 7\\=> 7^3 * x^{x-y} = 7\\=> x^{x-y} = 7/7^3\\=> x^{x-y} = 1/7^2$

As, x + y = 3, so y = 3-x

So,

$(x)^{x-(3-x)} = 1/7^2\\=> x^{2x - 3} = 7^{-2}$