Question

$(73 \times 73 + 48 \times 48 - 73 \times 48 \times 2)$
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Answer 1

Answer:

here we can apply the identity that,

$({a}^2+{b}^2-2ab)=(a-b)^2\\\\[\tex]</p><p>so </p><p></p><p>[tex] (73 \times 73 + 48 \times 48 - 73 \times 48 \times 2)\\ =(73-48)^2=(25)^2=625\\</p><p>\mathcal{PLS. \:MARK\: AS \:BRAINLIEST}$