Question

$7ax2 + 14ax + 7a =$

Answer 1

↪7ax² + 14ax + 7a = 0

By factorizing,

➡7ax² + 7ax + 7ax + 7a = 0

➡7ax(x + 1) + 7a(x + 1) =0

➡(7ax + 7a) (x +1) =0

equating both the factors to zero to find their roots

➡x = -1

➡x = -1

Hence solved

Answer 2

Answer:

7ax`2+14ax+7a

=7a(X`2+2x+1)

=7a(x+1)`2

=7a(x+1)(x+1)