Chemistry, asked by thapaavinitika6765, 5 months ago

7r\left(4rs-5s^2\right)-3r\left(-6rs+15s^2\right)-4r\left(-rs-2s^3\right)​

correct answer needed ..............

Answers

Answered by Anonymous
2

7r\left(4rs-5s^2\right)-3r\left(-6rs+15s^2\right)-4r\left(-rs-2s^3\right)

=28r^2s-35rs^2-3r\left(-6rs+15s^2\right)-4r\left(-rs-2s^3\right)

=28r^2s-35rs^2+18r^2s-45rs^2-4r\left(-rs-2s^3\right)

=28r^2s-35rs^2+18r^2s-45rs^2+4r^2s+8rs^3

=50r^2s+8rs^3-80rs^2

Hope it Helped !!!

Answered by brainlyboy11140
1

f^2+ax^2-b^+3\rott2

This is answer

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