Question

$7yx \times 1xyx25 \div 1(2912 \div 141)6x \times .y1. \frac{ - (29 + + {6 {x.6113 {3 = }^{?} }^{?} }^{?} }{?}$
plzz answer me fast
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Answer 1

$\huge\red{\underline{\overline{\mathbb{√\ηsωεя:-}}}}$

Answer 2

Que ) A coin is tossed two times. Find the probability of getting at most one head? ....

Solution-:

When two coins are tossed, the total no of outcomes = 2² = 4

i.e. (H, H) (H, T), (T, H), (T, T)

Where,

H represents head

T represents the tail

We need at most one head, that means we need one head only otherwise no head....

Possible outcomes = (H, T), (T, H), (T, T)

Number of possible outcomes = 3

Hence, the required probability = ¾