Question

${8}^{1} \times {3}^{0} - {2}^{2} \times {5}^{0} + {3}^{2} \times {4}^{1}$
Simplify and write the result in exponential form​

Answer 1

$\bf{Qestion}$

${8}^{1} \times {3}^{0} - {2}^{2} \times {5}^{0} + {3}^{2} \times {4}^{1}$

$\: \: \ \: \boxed{ \sf{ \rightarrow{a}^{1} = a }}\\ \: \: \: \ \boxed{ \sf{\rightarrow \: {a}^{0} = 1} }$

$\sf{8 \times 1 - 4 \times 1 + 9 \times 4}$

$\sf{ \: According \: to \: BODMAS \: rule:-}$

$\rightarrow{ \sf{Bracket }} \\ </p><p> \rightarrow { \sf{Of }} \\ </p><p> \rightarrow{ \sf{Division}} \\ </p><p> \rightarrow { \sf{Multiplication}} \\ </p><p>\rightarrow{ \sf{Addition}} \\ </p><p>\rightarrow{ \sf{Subtraction}}</p><p></p><p></p><p>$

Soo , The process is done accordingly :-

$\sf{8 - 4 + 36}$

$\: \sf{44 - 4} \\ \implies \:\sf{Ãñswēr} \: 40$