![8 {?}^{2} + 3x - 5 8 {?}^{2} + 3x - 5](https://tex.z-dn.net/?f=8+%7B%3F%7D%5E%7B2%7D++%2B+3x+-+5)
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If we have to factorise it then here is the answer.
8x² + 3x - 5 = 0
8x² + 8x - 5x - 5 = 0
8x(x + 1) - 5(x + 1) = 0
(8x - 5) (x + 1) = 0
Furthermore, you can find the value of x.
That is
x = 5/8 , -1
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