Question

$8 ^3 \times 8 ^{2} \times 8 ^ - 5$
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Answer 1

Answer:

$\huge 8 ^3 \times 8 ^{2} \times 8 ^ {- 5} \\ \huge = {8}^{3 + 2} \times 8 ^ {- 5 } \\ \huge= {8}^{5 - 5} \\ \huge = {8}^{0} \\ \huge = 1 \\ thus \:\\ \huge \fbox {8 ^3 \times 8 ^{2} \times 8 ^ {- 5} = 1}$

Answer 2

The question is:

${8}^{3} \times {8}^{2} \times {8}^{ - 5}$

= 8^3+2 * 8^-5

= 8^5-5

= 1

Hope It helps:)