Question

${8}^{ - 6} \times {8}^{b} = {8}^{4}$
Find the value of b..
$(\frac{1}{2} ) {}^{2b} \div ( \frac{1}{2} ) {}^{2} = ( \frac{1}{2}) {}^{4}$
Find the value of b..
​

Answer 1

1) ${8}^{ - 6} \times {8}^{b} = {8}^{4}$

${8}^{b}{-}{6} = {8}^{4}$

b = 4+6

$\boxed{b \: = \: 10}$

2) $(\frac{1}{2} ) {}^{2b} \div ( \frac{1}{2} ) {}^{2} = ( \frac{1}{2}) {}^{4}$

b = $\frac{6}{2}$

$\boxed{b \: = \: 3}$

Answer 2

Answer:

Hope it helps you...... ^_^