Question

$[{(8)}^ \frac{2}{3} \times 2^{ - 2} \div 6^{0} ] =$
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Answer 1

${\large{\sf{\color{lime}{★}} {Required \: \: Answer:}}}$

To Solve:

• {8⅔ × 2-² ÷ 6⁰}

Solⁿ:

• Any number with power of zero is 1

$( {8}^{ \frac{2}{3} } \times {2 }^{ - 2} \div {6}^{0} ) \\ \\ {8}^{ \frac{2}{3} } = \sqrt[3]{8} \times 2 \\ \\ = > 2 \times 2 = 4 \\ \\ {2}^{ - 2} = ({ \frac{1}{2}) }^{2} = \frac{1}{4} \\ \\ {6}^{0} = 1 \\ \\ 4 \times \frac{1}{4} \div 1 \\ \\ { \boxed{\pink{= 1}}}$

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Answer 2

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