Question

$8 sin^{2} a + 8 cos ^{2} a$
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Answer 1

Step-by-step explanation:

$8 { \sin ^{2} (a) } + 8 \cos ^{2} (a) \\ \\ = 8( { \sin ^{2} (a) } + { \cos }^{2} (a)) \\ \\ = 8 \times 1 \\ \\ = 8 \\ \\ \\ formula \: \: - \: \: \: { \sin {}^{2} ( \alpha ) } + { \cos ^{2} ( \alpha ) } = 1$