Math, asked by luthogiwu, 3 months ago

8^x{} .16^{x-1} =1\\

Answers

Answered by AstroPaleontologist
1

Question :-

 {8}^{x} . {16}^{x - 1}  = 1

To Find:-

  • x

Here, (.) represents (×)

 {8}^{x}  \times  {16}^{x - 1}  = 1

Let us express the bases as primes with powers.

( {2^{ 3} })^{x}  \times  { {(2}^{4}) }^{x - 1} = 1

As we know that,

 {( {a}^{m}) }^{n}  =  {a}^{m \times n}

'a' being a whole number.

 {2}^{3 \times x}  \times  {2}^{4(x - 1)}  = 1

 {2}^{3x}  \times  {2}^{4x - 4}  = 1

By using the exponent law,

 {a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

Here,

  • a = 2

 {2}^{3x + 4x - 4}  = 1

 {2}^{7x - 4}  = 1

The only possible way that 2 power any number is equal to 1, is when the power is 0.

 {a}^{0}  = 1

Hence, By taking the powers alone,

7x - 4 = 0

7x =4

x =  \dfrac{4}{7}

Therefore in order to be LHS = RHS, x takes a value of 4/7.

Hope it helps

Happy day!

Answered by BrainlyKingShree
1

Step-by-step explanation:

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