Question

$8 {x}^{3} + {y}^{3} +27 {z}^{3} - 18xyz$​

Factorise it!
No lame answers please! ​

Answer 1

Answer:

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Answer 2

${\huge {\underline {\mathfrak {\blue {Answer}}}}}$

❇GiVeN:

$8 {x}^{3} + {y}^{3} +27 {z}^{3} - 18xyz$

❇SoLuTiOn:

Here we have,

$8 {x}^{3} + {y}^{3} +27 {z}^{3} - 18xyz$

$={ 2x}^{3} + {y}^{3} + {3z}^{3} - 3 (2x)(y)(3z)$

$= (2x + y + 3z)[({2x})^{2} + {y}^{2} +({3z})^{2}-(2x)(y) - (y)(3z) - (2x)(3z)]$

$=(2x + y + 3z)({4x}^{2} + {y}^{2} + 9{z}^{2} - 2xy - 3yz -6xz)$

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