Question

$879$
Helping me ​

Answer 1

$\huge\star\bold\red{ANSWER}$

=>(3a-2b)²-(3a+2b)²

using identity a²-b²=(a+b)(a-b)

$\star\bold\red{Then,}$

=>$[3a-2b+(3a+2b)][3a-2b-(3a+2b)]$

=>$(6a)(-4b)$

=>$-24ab$ .....ans...[option b is correct]

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