Question

$8a {}^{3} - \frac{1}{27} factorise \: the \:folling$
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Answer 1

Answer:

(2a - 1/3) (4a² + 2a/3 + 1/9)

Step-by-step explanation:

==: 8a³ - 1/27                       [a³ – b³ = (a – b) (a² + ab + b²)]

==: (2a)³ - (1/3)³

==: (2a - 1/3) (4a² + 2a/3 + 1/9)

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Answer 2

Answer:

$8 {a}^{3} - \frac{1}{27} = {2a}^{3} - \frac{1}{{3}^{3} } \\ \\ = ( {2a} + \frac{1}{3} )( {4a}^{2} + \frac{1}{9} + \frac{2a}{3})$