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priya0903:
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\begin{lgathered}We \: \: know \: \: that ,\: \\ \\ \boxed{ (x + y) {}^{3} = x {}^{3} + y {}^{3} + 3x {}^{2} y + 3xy {}^{2} }\\ \\ \\ By \: using \: this \: \: formula, \:\end{lgathered}Weknowthat,(x+y)3=x3+y3+3x2y+3xy2Byusingthisformula,
\begin{lgathered}8x {}^{3} + 27y {}^{3} + 36x {}^{2} y + 54xy {}^{2} \\ \\ = (2x) {}^{3} +( 3y) {}^{3} + 3 \times 4x \times 3y + 3 \times 2x \times 9y \\ \\ =( 2x) {}^{3} + (3y) {}^{3} + 3 \times (2x) {}^{2} \times 3y + 3 \times 2x \times (3y) {}^{2} \\ \\ = (2x + 3y) {}^{3} \\ \\ = (2x + 3y)(2x + 3y)(2x + 3y)\end{lgathered}8x3+27y3+36x2y+54xy2=(2x)3+(3y)3+3×4x×3y+3×2x×9y=(2x)3+(3y)3+3×(2x)2×3y+3×2x×(3y)2=(2x+3y)3=(2x+3y)(2x+3y)(2x+3y)
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\begin{lgathered}We \: \: know \: \: that ,\: \\ \\ \boxed{ (x + y) {}^{3} = x {}^{3} + y {}^{3} + 3x {}^{2} y + 3xy {}^{2} }\\ \\ \\ By \: using \: this \: \: formula, \:\end{lgathered}Weknowthat,(x+y)3=x3+y3+3x2y+3xy2Byusingthisformula,
\begin{lgathered}8x {}^{3} + 27y {}^{3} + 36x {}^{2} y + 54xy {}^{2} \\ \\ = (2x) {}^{3} +( 3y) {}^{3} + 3 \times 4x \times 3y + 3 \times 2x \times 9y \\ \\ =( 2x) {}^{3} + (3y) {}^{3} + 3 \times (2x) {}^{2} \times 3y + 3 \times 2x \times (3y) {}^{2} \\ \\ = (2x + 3y) {}^{3} \\ \\ = (2x + 3y)(2x + 3y)(2x + 3y)\end{lgathered}8x3+27y3+36x2y+54xy2=(2x)3+(3y)3+3×4x×3y+3×2x×9y=(2x)3+(3y)3+3×(2x)2×3y+3×2x×(3y)2=(2x+3y)3=(2x+3y)(2x+3y)(2x+3y)
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