Question

$8x ^{3} - 27y ^{3}$
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Answer 1

$\red{\underline{\bf{Question:-}}}$

$8x ^{3} - 27y ^{3}$

$\red{\underline{\bf{Formula\:used:-}}}$

a³ - b³ = (a - b)(a² + b² + ab)

$\red{\underline{\bf{Answer:-}}}$

8x³ = (2x)³

27y³ = (3y)³

$\underline{So,}$

8x³ - 27y³

=(2x)³ - (3y)³

Here 2x is a and 3y is b

Using above formula,

= (2x - 3y)( 4x² + 9y² + 6xy)

Answer 2

Step-by-step explanation:

$8 {x}^{3} - 27 {y}^{3} \\ \\ = {2x}^{3} - {3y}^{3} \\ \\ = ( {(a)}^{3} - {(b)}^{3} ) = {(a - b)}^{3} ( {a}^{2} + ab \\ + {b}^{2} ) \\ \\ = {(2x - 3y)}^{3} (4 {x}^{2} + 6xy + \\ \\ 9 {y}^{2} )$