Math, asked by yukseltann, 8 months ago

8yy' = -\sqrt{x-4xy^{4} }

find the general solution of the differential equation

Answers

Answered by baliram16
1

8y²=( x-4xy)²

8y²=x²+(4xy)²-2(x)(4xy)

8y²=x²+16x²y²-8x²y

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