Math, asked by sartajbir1, 6 months ago

$9 {}^{2} {}^{p - 1} \div 81 = 9$

Answers

Answered by BabyBold07

2

${9}^{2p - 1} \div 81 = 9 \\ \frac{ {9}^{2p - 1} }{ {9}^{2} } = 9 \\ {9}^{2p - 1 - 2} = 9 \\ {9}^{2p - 3} = 9 \\ 2p - 3 = 1 \\ 2p = 4 \\ p = 2$

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