Question

$9 {}^{3 \div 2} - 3 \times {5}^{0} - \frac{1}{81} {}^{ - 1 \div 2} = 15$
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Answer 1

Step-by-step explanation:

Use grouping to factorise the numerator and take out the common factor \(ax\) in the denominator\[\frac{\left(ax - ab\right) + \left(x - b\right)}{a{x}^{2} - abx} = \frac{a\left(x - b\right) + \left(x - b\right)}{ax\left(x - b\right)}\]

Take out common factor \(\left(x-b\right)\) in the numerator\[=\frac{\left(x - b\right)\left(a + 1\right)}{ax\left(x - b\right)}\]

Cancel the common factor in the numerator and the denominator to give the final answer\[= \frac{a + 1}{ax}\]

Answer 2

Answer:

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