Math, asked by aniket2352, 11 months ago


9 {x}^{2}  - 3x - 2

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Answered by gaurav2013c
2
9x^2 - 3x - 2 = 0

=> 9x^2 - 6x + 3x - 2 = 0

=> 3x( 3x - 2) + 1(3x - 2) = 0

=> (3x-2) (3x+1) = 0

x = 2/3 and (-1/3)
Answered by Anonymous
0

 = 9 {x}^{2}  - 6x  +  3x - 2 \\  =3x(3x - 2)  + 1(3x - 2) \\  =(3x + 1)(3x - 2)
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