Question

$9 {x}^{2}- 6x + 26 = 0$
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Answer 1

Step-by-step explanation:

Factoring 9x2-6x-26 =0

The first term is, 9x2 its coefficient is 9 .

The middle term is, -6x its coefficient is -6 .

The last term, "the constant", is -26

Step-1 : Multiply the coefficient of the first term by the constant 9 • -26 = -234

Step-2 : Find two factors of -234 whose sum equals the coefficient of the middle term, which is -6 .

-234 + 1 = -233

-117 + 2 = -115

-78 + 3 = -75

-39 + 6 = -33

-26 + 9 = -17

-18 + 13 = -5

-13 + 18 = 5

-9 + 26 = 17

-6 + 39 = 33

-3 + 78 = 75

-2 + 117 = 115

-1 + 234 = 233