Question

$9 {x}^{2} + 6xy + {y}^{2}$
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Answer 1

(3x + y)^2 is your answer.

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Answer 2

$answer... \: \\ \\ 9 {x}^{2} + 6xy + {y}^{2} \\ (3 {x})^{2} + 2 \times 3x \times y + ({y})^{2} \\ \\ using \: identity - {x}^{2} + 2xy + \\ \: \: \: \: \: \: \: \: \: \: \: \\ {y}^{2} = (x + {y})^{2} \\ \: x = 3x \: \: \: \: \: \: \: y = y \: \: \\ therefore \\ = > (3x + {y})^{2} \\ = > (3x + y)(3x + y) \\ \\ \\ \\ hope \: it \: is \: helpful \: to \: you \: \\ \\ \\ please \: mark \: as \: \beta r \alpha inliest.....$