Question

$9 {y}^{2} - 12 \: y + 2 = 0$
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Answer 1

$9 {y}^{2} - 12y + 2 \\ {b}^{2} - 4ac = 144 - 72 = 72 \\ y = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac } }{2a} \\ y = \frac{12 \frac{ + }{} \sqrt{72} }{18} = \frac{12 \frac{ + }{} 6 \sqrt{2} }{18} = \frac{2 \frac{ + }{} \sqrt{2} }{3}$

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