Question

$98 {y}^{2 } + 168yz + 72 {z}^{2}$
factorise the expression​

Answer 1

To factorise:-

• 98y²+168yz+72z²

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Solution:-

By rearranging the given equation:

=> 98y²+72z²+168yz

Now adjusting it in the form of any algebraic identity.

=> (7√2y)²+ (6√2z)²+2(7√2y)(6√2z)

Now we can see that this is in the form of a²+b²+2ab=(a+b)² where a=7√2y and b=6√2z.

So,

=> (7√2y+6√2z)²

Hence factorised

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