Question

$99 {a}^{2} - 222ab + 99b {}^{2}$
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Answer 1

Answer:

(9a - 11b) • (11a - 9b)

Step-by-step explanation:

STEP1:

Equation at the end of step 1

((99 • (a2)) - 202ab) + (32•11b2)

STEP 2:

Equation at the end of step 2:

((32•11a2) - 202ab) + (32•11b2)

STEP3:

Trying to factor a multi variable polynomial

3.1 Factoring 99a2 - 202ab + 99b2

Try to factor this multi-variable trinomial using trial and error

Found a factorization : (9a - 11b)•(11a - 9b)

Answer 2

Hello dear

Hello dearyour question is wrong

Factorising 99a2 - 202ab + 99b2

((99 • (a^2)) - 202ab) + (3^2•11b^2)

((3^2•11a^2) - 202ab) + (3^2•11b^2)

Final result :

(9a - 11b) • (11a - 9b)