Question

$(9p - 5q)^2 + 180pq = (9p - 5q)^2$
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Answer 1

Step-by-step explanation:

${(9p - 5q)}^{2} + 180pq = {(9p - 5q)}^{2}$

$180pq = 0$

$p = 0 \: q = 0$

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Answer 2

Answer:

$(9p - 5q)^2 + 180pq = (9p - 5q)^2$

by transferring them

$(9p - 5q)^2- (9p + 5q)^2 = - 180pq$

opening whole square

$(9p - 5q)^2- (9p - 5q)^2 = - 180pq$

${81p}^2 + {25q}^2 -90pq -{81p}^2 - {25q}^2 -90pq = - 180pq$

$-90pq -90pq = - 180pq$

$-180pq = - 180pq$