Question

$9x^{2} + 24x + 16 = 0$
$solve \: this \: question$

Answer 1

(3x-4)^2=0
3x-4=0
x=4/3

Answer 2

$9x^2 + 24x + 16 = 0 \\ \\ = (3x)^2 + (2 * 3x * 4) + 4^2 = 0 \\ \\ = (3x + 4)^2 = 0 \\ \\ 3x + 4 = \sqrt{0} = 0 \\ \\ 3x = - 4 \\ \\ x = \frac{- 4}{3}$

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