Question

$9x 2 - 3ax + 1 = 0$
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Answer 1

Answer:

Here's your answer

a =9 ,b= -3a ,c= 1

D= b^2-4ac

D= 9a^2-36

if the polynomial have real and equal roots

so D=0

9a^2-36=0

9a^2= 36

a^2= 36/9

a^2=4

a=√4= 2

So the value of a is 2 ....

Hope it helps ✌