Question

${9x}^{2} - 9(a + b)x + ( {2a}^{2} + 5ab + {2b}^{2} ) = 0$
solve it plz​

Answer 1

Explanation:

Step-by-step explanation:

9x² - 9( a+b)x + (2a² + 5ab + 2b² ) = 0

BY QUADRATIC FORMULA -

9 ( a + b ) ± √ 81(a+b)² - 4 (9)( 2a² + 5ab + 2b² ) / 2( 9 )

RESOLVING D

81 ( a + b ) ² - 4 ( 9 )( 2a²+5ab+2b² )

81( a² + b² + 2ab ) - 36( 2a²+5ab+2b² )

81a²+81b²+ 162ab - 72a²- 180ab - 72b²

9a² + 9b² -18ab = [3(a+b)]²

D = [3(a+b)]² ; √D = 3( a+b )

9( a+b ) ± 3 ( a + b ) / 18