Question

$9x {}^{2} - kx + 16 = 0$
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Answer 1

Answer:

a=9, b= -k, c=16

$d = {b }^{2} - 4ac$

$= - {k}^{2} - 4 \times 9 \times 16 \: \: = 0$

${k}^{2} - 276$

$k = \sqrt[ + - ]{276}$

$k = + - 24$