Question

$9x + 3y + 12 = 0 \\ 18x + 6y + 24 = 0$
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Answer 1

Hey

Here,

a1 = 9

b1 = 3

c1 = 12 and

a2 = 18

b2 = 6

c2 = 24

a1/a2 = 9/18 = 1/2

b1/b2 = 3/6 = 1/2

c1/c2 = 12/24 = 1/2

Here

a1/a2 = b1/b2 = c1/c2

Thus

The both lines are dependent lines and have infinitely many solutions

Answer 2

here in the question we can see that the 2nd poly nominal is doubled which means X2

so,

= 2(9x + 3y +12)

= 2(0)

= 0

hope it helped...

pls leave a thank you