Math, asked by aishowrya, 1 year ago


 {a}^{0}  \div  {a}^{ - 1}  =  {a}^{x}
Solve it :)

Answers

Answered by Swarup1998
1
➡HERE IS YOUR ANSWER⬇

 {a}^{0}   \div  {a}^{ - 1}  =  {a}^{x} \\  \\ or \:  \:  \frac{1}{ {a}^{ - 1} }   =  {a}^{x}  \\  \\ or \:  \:  {a}^{1}  =  {a}^{x}

Comparing, we get

x = 1.

⬆HOPE THIS HELPS YOU⬅
Answered by Anonymous
5
Hi there !!

Here's your answer

Given,

to find the value of a in:

 {a}^{0}   \div  {a}^{ - 1}  =  {a}^{x}
Writing a^0 ÷ a^-1 in the form of numerator/denominator, we have,

 \frac{ {a}^{0} }{ {a}^{ - 1} }  =  {a}^{x}
Now,

using the law of exponents, which in this case is
a^m/a^n = a^m-n,

we have,

 { {a}^{0 - ( - 1)} }^{}  =  {a}^{x}
Since - and - makes a positive sign, we have,

 {a}^{0 + 1}  =  {a}^{x}


 {a}^{1}  =  {a}^{x}
Cancelling a in LHS and RHS,
we have,

1 = x
or x = 1

So,
the value of x is 1

Anonymous: if any doubts, comment below :-)
Anonymous: thanks for the brainliest :D
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