Math, asked by mnshpopat, 4 months ago


(a + 1 \2a)
Whole square of the above equation

Answers

Answered by manissaha129
2

Answer:

( {a +  \frac{1}{2a}) }^{2}  \\  {a}^{2} +  \frac{1}{4 {a}^{2} }   + 2 \times a \times  \frac{1}{2a}  \\   \boxed{{a}^{2}   + \frac{1}{4 {a}^{2} }  + 1}

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