![{a }^{2} - 12a - 16 {a }^{2} - 12a - 16](https://tex.z-dn.net/?f=+%7Ba+%7D%5E%7B2%7D++-+12a+-+16+++)
Tell me the answer fast guys in step by step.......
Answers
Answered by
1
Answer:
a²-12a-16
a=-b±√b²-4ac/2a
a=-(-12)±√(-12)²-4(1)(-16)/2(1)
a=12±√144+64/2
a=12±√208/2
a=12+√208/2 or a=12-√208/2
Similar questions