Math, asked by baby3419, 1 year ago


a { }^{2}  + 4b {}^{2}  - 4ab - 4c {}^{2}
factorize ​


sivaprasath: (a - 2b + 2c)(a - 2b + 2c)

Answers

Answered by mahamahmood95
2

Step-by-step explanation:

a²+4b²-4ab-4c²

using the formula a² -2ab+b²=(a-b)²

(a-2b)² -(2c)²

now using a² -b²=(a+b)(a-b)

you get,

(a-2b-2c)(a-2b+2c)

this is your answer


baby3419: but I am confuse . How to answer come
mahamahmood95: just follow the steps
baby3419: ok,thanks
mahamahmood95: you're welcome
Answered by arnab2261
10

 {\huge {\mathfrak {Answer :-}}}

✨THERE IT GOES

________________

a^2 + 4b^2 - 4ab - 4c^2

= a^2 - 2 * 2b * a + (2b)^2 - (2c)^2

= (a - 2b)^2 - (2c)^2

= (a - 2b + 2c)(a - 2b - 2c)

________________

✨️ HOPE THIS HELPS ✨

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