Question

${a}^{2} - a(x + 3b) + 3bx$
please answer it​

Answer 1

As per Given

$= > a {}^{2} - a(x + 3b) + 3bx \\ = > {a}^{2} - ax - 3ab + 3bx \\ = > a(a - x) - 3b(a - x) \\ = > (a - 3b)(a - x)$

In order to find zero of quadratic equation with variable a

$so \\ (a - 3b)(a - x) = 0 \\ a = 3b \: and \: a = x$

Hope It Helps

Answer 2

$</p><p>a^2 - a(x + 3b) + 3bx \\ </p><p>a^2 - ax - 3ab) + 3bx \\ </p><p>a(a - x) - 3b(a - x) \\ </p><p>( a - x)(a - 3b) \\ </p><p>in \: order \: to \: find \: \\ quadretic \: equation \: with \: variable a \: </p><p>so \\ </p><p>( a - x)(a - 3b)= 0 \\ </p><p>a = x \: and \: 3b</p><p></p><p>$