Factorise the following (class 8th)
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Answered by
6
Hi !
Solution :-
=> a² + ac + bc - b²
=> a² - b² + ac + bc
=> (a - b ) ( a + b) + c ( a + b )
=> ( a + b ) ( a - b + c) Answer
_______________________
Hope it helps you !!!
@Rajukumar111
Solution :-
=> a² + ac + bc - b²
=> a² - b² + ac + bc
=> (a - b ) ( a + b) + c ( a + b )
=> ( a + b ) ( a - b + c) Answer
_______________________
Hope it helps you !!!
@Rajukumar111
Answered by
1
Factorize:- a²+ac+bc-b²
Now, We will do like this,
⇒a²-b²+ac+bc
{We know that the factor formula for a²-b²=(a+b)(a-b)}
⇒(a+b)(a-b)+ac+bc
Taking out 'c' as common in ac+bc
⇒(a+b)(a-b)+c(a+b)
Now (a+b) are taken as common,
⇒(a+b)(a-b+c)
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