Question

$a^2- b^2= (a + b) (a - b)$ का उपयोग करते हुए, निम्नलिखित मान ज्ञात कीजिए :
(i) $51^2- 49^2$ (ii) $(1.02)^2- (0.98)2$ (iii) $153^2- 147^2$ (iv) $12.1^2- 7.9^2$

Answer 1

Answer Step-by-step explanation:

1) 51² –  49²  

सर्वसमिका के उपयोग से , a² -  b² = (a + b) (a - b)

= (51 + 49)(51 - 49)

= 100 x 2

= 200

 

2) (1.02)² – (0.98)²

सर्वसमिका के उपयोग से , a² -  b² = (a + b) (a - b)

= (1.02 + 0.98)(1.02 - 0.98)

= 2 x 0.04

= 0.08

 

3) 153² – 147²

सर्वसमिका के उपयोग से , a² -  b² = (a + b) (a - b)

= (153 + 147)(153 - 147)

= 300 x 6

= 1800

 

4) 12.1² – 7.9²

सर्वसमिका के उपयोग से , a² -  b² = (a + b) (a - b)

= (12.1 + 7.9)(12.1 - 7.9)

= 20 x 4.2

= 84

आशा है कि यह उत्तर आपकी अवश्य मदद करेगा।।।।  

इस पाठ से संबंधित कुछ और प्रश्न :

सर्वसमिकाओं के उपयोग से निम्नलिखित मान ज्ञात कीजिए : (i) $71^2$ (ii) $99^2$ (iii) $102^2$ (iv) $998^2$ (v) $5.2^2$ (vi) $297 \times 303$ (vii) $78 \times 82$ (viii) $8.9^2$ (ix) $1.05 \times 9.5$

https://brainly.in/question/10955478

दर्शाइए कि : (i) $(3x + 7)^2- 84x = (3x - 7)^2$ (ii) $(9p - 5q)^2+ 180pq = (9p + 5q)^2$ (iii) $(\frac{4}{3} m-\frac{3}{4} n)^2+2mn=\frac{16}{9} m^2+\frac{9}{16} n^2$ (iv) $(4pq + 3q)^2- (4pq - 3q)^2= 48pq^2$ (v) $(a - b) (a + b) + (b - c) (b + c) + (c - a) (c + a) = 0$

https://brainly.in/question/10766250

Answer 2

Answer:

$\huge{\boxed{\boxed{\bf{(i)=200, (ii)=0.08,(iii)=1800,(iv)=84}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\bf{SOLUTION-}}}}}$

>>TO SOLVE THESE QUESTIONS WE USE THE BASIC FORMULA .

${a}^{2} - {b}^{2} =( a + b) \: (a - b)$

>> FIRST QUESTION:

$= )( {51})^{2} - (49)^{2} \\ = )(5 1 + 49)(51 - 49) \\ = )100 \times 2 \\ = )<strong>200</strong>$

>> SECOND QUESTION:

$= )( {1.02})^{2} - ({0.98})^{2} \\ = )(1.02 + 0.98)(1.02 - 0.98) \\ = )(2) \times (0.04) \\ = )<strong>0.08</strong>$

>> THIRD QUESTION:

$= ) ({153})^{2} - (147)^{2} \\ = )(153 + 147)(153 - 147) \\ = )300 \times 6 \\ = )<strong>1800</strong>$

>> FOURTH QUESTION:

$= )( {12.1})^{2} - (7.9) ^{2} \\ = )(12.1 + 7.9)(12.1 - 7.9) \\ = )20 \times 4.</u><u>2</u><u> \\ = )<strong>8</strong></u><u>4</u><u>$

$\huge{\boxed{\boxed{\bf{(i)=200, (ii)=0.08,(iii)=1800,(iv)=84}}}}$