Math, asked by dharvipadmani, 8 months ago


 {a}^{2}  +  {b}^{2}  +  {c}^{2} - ab + 2ab + 2bc - 2ca

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Answered by Anonymous
2

Given :  {a}^{2} + {b}^{2} + {c}^{2} - ab + 2ab + 2bc - 2ca

 = {a}^{2} + {b}^{2} + {c}^{2} + ab + 2bc - 2ca

 = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc - 2ac

 = {a}^{2} + {b}^{2} + {c}^{2} + 2bc - 2ac

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