Question

${a}^{2} {b}^{2} {x}^{2} - ( {4b}^{4} - {3a}^{4})x - 12 {a}^{2} {b}^{2} = 0$
Solve the equation using formula. Please don't sspam

Answer 1

step by step

ANSWER

a2b2x2−(4b2−3a4)x−12a2b2=0

Therefore, the roots are:

x=2a2b2(4b2−3a4)±(4b2−3a4)2+4a2b2(12a2b2)=2a2b2(4b2−3a4)±9a8+16b4−24a4b2+48a4b4=2a2b2(4b2−3a4)±(4b2+

Answer 2

Answer:

ash.....I am sorry....T-T

pls don't hate me.....