Question

${a}^{3} + 3{a}^{2} b + 3a {b}^{2} + 2 {b}^{3} \: factorize$

Answer 1

hey mate
here's the solution

Answer 2

$\mathfrak{ANSWER}$


a³ + 3a²b + 3ab² + 2b³


= a³ + 3a²b + 3ab² + b³ + b³


= ( a )³ + 3( a )²b + 3a( b )² + ( b )³ + b³


= ( a + b )³ + b³


= ( a + b )³ + ( b )³


= ( a + b + b )[ ( a + b )² - ( a + b )( b ) + ( b )²]


= ( a + 2b )( a² + 2ab + b² - ab - b² + b²)


= ( a + 2b )( a² + ab + b² )


[
NOTE :- Identities used

( a + b )³ = a³ + 3a²b + 3ab² + b³

( a + b )² = a² + 2ab + b²

a³ + b³ = ( a + b )( a² - ab + b²)
]