Math, asked by meghraj9719, 6 months ago


 {a}^{3} - 6 {a}^{2} + 11a - 6

Answers

Answered by drashtimaisuriya1718
1

Step-by-step explanation:

a3-6a2+11a-6=0

a3-6a2+11a=6

a(a2-6a+11)=6

a(a2-6a+11-6)=0

a2-6a+11-6=0/a

a2-6a+5=0

a2-5a-1a+5=0

a(a-5)-1(a-5)=0

(a-1)(a-5)=0

a-1=0 or a-5=0

a=1 or. a=5

Answered by karthik4086
3

Step-by-step explanation:

i hope u would understand my answer

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