Math, asked by princepadmani015, 7 months ago


 {a}^{4 }  - a {}^{2}  + 16

Answers

Answered by Anonymous
3

Step-by-step explanation:

 {a}^{4 }  -  {a}^{2}  + 16 \\  =  >  {a}^{2}  + 16 = 0 \\ =  >   {a}^{2}  =  - 16 \\ =  >  a =   \sqrt{ - 16}  \\  =  > a = 4

Answered by Avni2348
3

Answer:

 {a}^{4}  -  {a}^{2}  + 16 \\  {a}^{2} + 16 = 0 \\  {a}^{2}  =  - 16 \\ a = 4

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