Question

$(a - 5) {}^{2} + (b - 6) {}^{2} = 0 \\ \\ find \: a + b - 3$
please answer fast and get brainliest​

Answer 1

See

The squares can never be negative

So

For their sum to be 0, they both need to be 0

Hence a=5 and b=6

So a+b-3=8

Answer is 8

Answer 2

Answer:

ANSWER 59 ab

Step-by-step explanation: