Question

$(a + b)^{2} = a^{2} + 2ab + b^{2}$
(3+4)^2
solve it with the given formula ​

Answer 1

3^2+4^2

=9+16

=25

25 is the answer

Answer 2

Answer:

$(3 + 4) ^{2} \\ = 3 {}^{2} + 2 \times 3 \times 4 + 4 {}^{2} \\ = 9 + 24 + 16 \\ = 9 + 40 \\ = 49 \\ hope \: that \: this \: helps$