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(a+b+c+a-b-c)(a+b+c-a+b+c)
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Answer:
4a(b+c)
Step-by-step explanation:
Let x= a+b+c & y = a-b-c
Hence our eqn reduces to the form x^2-y^2
=(x+y)(x-y)
Now we will substitute the value of x & y back
(x+y)(x-y)={( a+b+c) + (a-b-c)}{( a+b+c) - (a-b-c)}
= {2a}{a+b+c - a +b + c}
=2a(2b + 2c)
=4a(b+c)
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