Math, asked by wwwgagansidhu007, 8 months ago


(a + b) + c = a + (b + c)  a = \frac{1}{3} b =  \frac{2}{5}  c =  \frac{ - 3}{7}

Answers

Answered by VishnuPriya2801
3

Answer:

a = 27/14 ; b = -9/7 ; c = -15/14.

EXPLANATION:

From the question we observe that,

1/3 * b = -3/7

b/3 = -3/7

After cross multiplication we get,

7b = -9

b = -9/7

And in the same way,

2/5 * c = -3/7

2c/5 = -3/7

14c = - 15

c = -15/14

Now , substitute the values of a and c in

(a+b)+c = -3/7

(a +  \frac{ (- 9)}{7} ) +  \frac{ (- 15)}{14}  =  \frac{ - 3}{7}  \\  \\ ( \frac{7a - 9}{7} ) -  \frac{15}{14}  =  \frac{ - 3}{7}  \\  \\  \frac{2(7a - 9) - 15}{14}  =  \frac{ - 3}{7}  \\  \\  \frac{14a - 18 - 15}{14}  =  \frac{ - 3}{7}  \\  \\  \frac{14a - 33}{14}  =  \frac{ - 3}{7}  \\  \\

After cross multiplication we get,

7(14a - 33) = ( - 3)(14) \\  \\ 14a - 33 =  \frac{ - 42}{7}  \\  \\ 14a - 33 =  - 6 \\  \\ 14a =  - 6 + 33 \\  \\ 14a = 27 \\  \\ a =  \frac{27}{14}

Hence, a = 27/14 ; b = -9/7 ; c = -15/14.

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