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Given:
(a+b+c)(a+b-c)
To find:
multiple of the given expression
Solution:
simplify this expression by using the distributive property
a(a+b-c)+b(a+b-c)+c(a+b-c)
=a²+ab-ac+ab+b²-bc+ac+bc-c²
rearrage
=a²+b²-c²+ab+ab-bc+bc-ac+ac
=a²+b²-c²+2ab
Hence,(a+b+c)(a+b-c)=a²+b²-c²+2ab
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